SLE with four unknowns

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Solve the following system, and write down x4x_{4} value.

{x1+x2+x3=6x2x4=3x1x3=2x2+x3+x4=10\begin{cases} x_{1} + x_{2} + x_{3} = 6\\ x_{2} - x_{4} = -3\\ x_{1} - x_{3} = -2\\ x_{2} +x_{3} + x_{4} = 10 \end{cases}(Recall that if some of the unknowns is absent in the equation, we interpret it as if there is a zero coefficient before it.)

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