Linear programming problem

A shoemaking company "Old Balance Shoe" makes both sports and classic sneakers. It can produce 5000 sports and 3500 classic sneakers per day. The company makes a profit of $\$120$ on sports sneakers and a profit of $\$180$ on classic sneakers. The supply of leather is sufficient to produce at most 6500 sneakers per day. Let $x_1$ and $x_2$ represent the units of sports and classic sneakers that should be produced.

Select the correctly formulated linear program for this problem.

$A.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 < 6500 \\ x_1 = 5000 \\ x_2 = 3500$

$B.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 > 6500 \\ x_1 < 5000 \\ x_2 > 3500$

$C.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \le 6500 \\ x_2< 3500 \\ x_2 \ge 0$

$D.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \le 6500 \\ x_2, x_2 \ge 0$

$E.\\ Minimize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \ge 6500 \\ x_2, x_2 \ge 0$

$F.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \ge 6500 \\ x_1 <5000\\ x_2 < 3500 \\ x_1, x_2 \ge 0$

$G.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \ge 6500 \\ x_1 \le5000\\ x_2 \le 3500 \\ x_1, x_2 \le 0$

$H.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \ge 6500 \\ x_1 \ge5000\\ x_2 \ge 3500 \\ x_1, x_2 \le 0$

$I.\\ Maximize \ z = 120x_1 + 180x_2 \\ s.t.: \\x_1 + x_2 \ge 6500 \\ x_1 \ge5000\\ x_2 \ge 3500 \\ x_1, x_2 \ge 0$