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We already know the function limit. In this topic, we will learn what operations we can perform with it.

Operations with limits

Suppose we have two functions f(x)f(x) and g(x)g(x), and two limits lim⁡x→af(x)\lim\limits_{x \to a} f(x) and lim⁡x→ag(x)\lim\limits_{x \to a} g(x)

Then we can perform the following operations with limits:

1) Add

lim⁡x→af(x)+lim⁡x→ag(x)=lim⁡x→a(f(x)+g(x))\lim\limits_{x \to a}f(x) + \lim\limits_{x \to a}g(x)=\lim\limits_{x \to a}( f(x) + g(x) )2) Subtract

lim⁡x→af(x)−lim⁡x→ag(x)=lim⁡x→a(f(x)−g(x))\lim\limits_{x \to a}f(x) -\lim\limits_{x \to a}g(x)=\lim\limits_{x \to a}( f(x) - g(x) )3) Multiply

lim⁡x→af(x)⋅lim⁡x→ag(x)=lim⁡x→a(f(x)⋅g(x))\lim\limits_{x \to a}f(x) \cdot\lim\limits_{x \to a}g(x)=\lim\limits_{x \to a}( f(x) \cdot g(x) )4) If lim⁡x→ag(x)≠0\lim\limits_{x \to a} g(x) \ne 0, we can divide lim⁡x→af(x)\lim\limits_{x \to a} f(x) by lim⁡x→ag(x)\lim\limits_{x \to a} g(x)

lim⁡x→af(x)lim⁡x→ag(x)=lim⁡x→af(x)g(x)\dfrac{\lim\limits_{x \to a} f(x)}{\lim\limits_{x \to a} g(x)}=\lim\limits_{x \to a} \dfrac{f(x)}{g(x)}5) Multiply by a constant ccc⋅lim⁡x→af(x)=lim⁡x→a(c⋅f(x))c \cdot \lim\limits_{x \to a}f(x)=\lim\limits_{x \to a} (c \cdot f(x))6) Raise to a positive integer power nn

(lim⁡x→af(x))n=lim⁡x→a(f(x))n(\lim\limits_{x \to a} f(x))^n=\lim\limits_{x \to a} (f(x))^n

7) Extract nnth root, where nn is a positive integer

lim⁡x→af(x)n=lim⁡x→af(x)n\sqrt[n]{\lim\limits_{x \to a}f(x)}=\lim\limits_{x \to a} \sqrt[n]{f(x)}

Example

Let's do some practice and find the limit lim⁡x→1x4−3x2+14−x\lim\limits_{x \to 1} \dfrac{x^4 -3x^2+1}{4-x}We use the rules that we've considered above:

lim⁡x→1x4−3x2+14−x=lim⁡x→1(x4−3x2+1)lim⁡x→1(4−x)=lim⁡x→1x4−3lim⁡x→1x2+lim⁡x→11lim⁡x→14−lim⁡x→1x= =14−3⋅12+14−1=−13\lim\limits_{x \to 1} \dfrac{x^4 -3x^2+1}{4-x} = \dfrac{\lim\limits_{x \to 1} (x^4 -3x^2+1)}{\lim\limits_{x \to 1} (4-x)} = \dfrac{\lim\limits_{x \to 1} x^4 -3\lim\limits_{x \to 1} x^2 + \lim\limits_{x \to 1} 1}{\lim\limits_{x \to 1} 4-\lim\limits_{x \to 1} x} = \\ \ \\ =\dfrac{1^4-3 \cdot 1^2+1}{4-1} = - \dfrac{1}{3}

Conclusion

In this topic, we learned about operations with limits. If the limits of functions f(x)f(x) and g(x)g(x) both exist, then we can add these limits, subtract, multiply and divide (provided that the denominator is not 00), multiply by a constant, or raise to a power. These operations are very helpful in calculating all sorts of limits.

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