Does the system
{3x−2y+2z=15−3x−2y+2z=62y+2z=103x=5\begin{cases} 3x - 2y + 2 z = 15 \\ -3x - 2y + 2 z = 6 \\ 2y + 2 z = 10 \\ 3x = 5 \end{cases}⎩⎨⎧3x−2y+2z=15−3x−2y+2z=62y+2z=103x=5
have only one solution?
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