When a variable is captured in a closure, what happens to the variable?
Advanced lambda expressions
Variable is captured
Report a typo
Select one option from the list
___
By continuing, you agree to the JetBrains Academy Terms of Service as well as Hyperskill Terms of Service and Privacy Policy.
Create a free account to access the full topic
By continuing, you agree to the JetBrains Academy Terms of Service as well as Hyperskill Terms of Service and Privacy Policy.