MathAlgebraLinear algebraMatrix decomposition

Diagonalizing matrices

Condition

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$A$ is a matrix of a linear operator $\cal A$ . If there is a basis of $n$ -dimensional space consisting of the eigenvectors of the linear operator $\cal A$ matrix $A$ is diagonalizable. Is this condition necessary, sufficient, or both?

Select one option from the list

Necessary

Sufficient

Both

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