Computer scienceProgramming languagesJavaErrorless codeException handling

Throwing exceptions

Theory

The root of a number

Report a typo

Implement the sqrt method that computes the square root of a given number. If a negative number is passed the method should throw a java.lang.IllegalArgumentException with the message "Expected non-negative number, got ?", where ? is the passed negative number.

Use Math library to evaluate the square root.
Write a program in Java 17
import java.util.*;

public class Main {

public static double sqrt(double x) {
// write your code here
}

/* Do not change code below */
public static void main(String[] args) {
String value = new Scanner(System.in).nextLine();
try {
double res = sqrt(Double.parseDouble(value));
System.out.println(res);
} catch (IllegalArgumentException e) {
System.out.println(e.getMessage());
}
}
}
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