Computer scienceProgramming languagesJavaBasicsControl flow statements

Conditional statement

Theory

Leap year

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Find whether a given year is a leap year.

Just a reminder: a leap year is divisible by 4 AND NOT divisible by 100 OR divisible by 400 (for example, the year 2000 is a leap year, but the year 2100 will not be a leap year).

The program should work correctly for the years 1900 ≤ n ≤ 3000.

Output "Leap" (case-sensitive) if the given year is a leap year, and "Regular" otherwise.

It is enough to write a simple conditional statement to solve this task.

Sample Input 1: 

2100

Sample Output 1: 

Regular

Sample Input 2: 

2000

Sample Output 2: 

Leap
Write a program in Java 17
import java.util.Scanner;

class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
// start coding here
}
}
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