MathAnalysisCalculusIntegrals

Introduction to Integrals

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What is the area under the curve for this function f(x)f(x), between x=11x=11 and x=24x=24? Given that we know its antiderivative to beF(x)=512−24⋅sin⁡(x6)−60⋅e(1−x)/62F(x)=512-24 \cdot \sin\left(\frac{x}{6}\right)-60 \cdot e^{(1-x)/62}

Round to the nearest integer.

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