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You already know the definition of a derivative of a function and you know how to find a derivative of polynomials, trigonometric, logarithmic functions. In this topic, we will consider another type of functions: exponential functions, and learn how to find the derivatives of such functions.

An exponential function

An exponential function is a function

f(x)=axf(x) = a^xwhere aa is called the base of the degree, and xx is the exponent. Notice that a0a \geqslant 0.

A derivative of this function is(ax)=axlna(a^x)' = a^x \cdot \ln aSo, we take the function axa^x and multiply it by the natural logarithm of aa.

Let's practice!

Consider a function f(x)=8xf(x) = 8^x. We use the rule that we discussed above to find the derivative of this function:

(8x)=8xln8(8^x)' = 8^x \cdot \ln 8Let's consider another example: g(x)=3x2g(x) = 3^{x^2}. We find the derivative of g(x)g(x) using the formula for the exponential function, and since the degree is a more complex expression than just xx, we also multiply it by the derivative of the degree, that is

(3x2)=3x2ln3(x2)=3x22xln3\left(3^{x^2}\right)' = 3^{x^2} \cdot \ln 3 \cdot (x^2)' = 3^{x^2} \cdot 2x \cdot \ln 3Now let's look at another example: h(x)=tan(3x)h(x) = \tan(3^x). It is a composite function, so we need the chain rule to find the derivative:

(tan(3x))=1cos23x(3x)=3xln3cos23x\left(\tan(3^x)\right)' = \dfrac{1}{\cos^2 3^x} \cdot (3^x)' = \dfrac{3^x \ln 3}{\cos^2 3^x}

Conclusion

In this topic we have learned about an exponential function and its derivative. If we have a function f(x)=axf(x) = a^x and want to find its derivative, we take the function axa^x and multiply it by the natural logarithm of aa. Also, we have considered a few examples.

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