What is an invalid way to create an instance of a functional interface?
Functional interfaces
An invalid way to create a functional interface
Report a typo
Select one option from the list
___
By continuing, you agree to the JetBrains Academy Terms of Service as well as Hyperskill Terms of Service and Privacy Policy.
Create a free account to access the full topic
By continuing, you agree to the JetBrains Academy Terms of Service as well as Hyperskill Terms of Service and Privacy Policy.